【问题】

xxxxxxxxxx22 1/ 分类页样式 began /2.category-list-link:hover{3 transform: scale(1.1);4 box-shadow: 10px 10px 15px 2px rgba(0,0,0,.12), 0 0 6px 0 rgba(104, 104, 105, 0.1);5 border-radius: 15px;6 padding: 6px 16px;7 margin-left: 0px;8 font-size: 16px;9 transition-duration: 0.15s;10 //display:flex;11}12a.category-list-link:before{13 top: 10px;14 width: 18px;15 height: 18px;16 content: “📚”;17 margin-right: 5px;18 font: normal normal normal 14px/1 FontAwesome;19 font-size: 15px;20 line-height: 18px;21}22/ 分类页样式 end /css

（1）输出结果是最简分数（可以是带分数）；

（2）分母为1，只输出分子。

【输入形式】

提示“Input x: ”，输入第一个分数。如：1/6

提示“Input y: ”，输入第二个分数。如：2/9

【输出形式】

提示并输出+、-、*、/的结果，如

x+y=7/18

x-y=-1/18

x*y=1/27

x/y=3/4

【样例输入】

Input x: 1/6

Input y: 2/9

【样例输出】

x+y=7/18

x-y=-1/18

x*y=1/27

x/y=3/4

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#include  <iostream>
#include  <cmath>
using  namespace  std;
class  CFraction
{
private:
    int  nume;    //  分子
    int  deno;    //  分母
public:
    CFraction(int  nu = 0, int  de = 1) :nume(nu), deno(de) {}
    void simplify();

    //输入输出的重载
    friend  istream &operator>>(istream &in, CFraction &x);
    friend  ostream &operator<<(ostream &out, CFraction x);

    friend  CFraction  operator+(const  CFraction &c1, const  CFraction &c2);    //两个分数相加，结果要化简
    friend  CFraction  operator-(const  CFraction &c1, const  CFraction &c2);    //两个分数相减，结果要化简
    friend  CFraction  operator*(const  CFraction &c1, const  CFraction &c2);    //两个分数相乘，结果要化简
    friend  CFraction  operator/(const  CFraction &c1, const  CFraction &c2);    //两个分数相除，结果要化简

};

void CFraction::simplify()
{
    int nume_ = abs(nume), deno_ = abs(deno); // 保存原分数

    if (nume < 0 && deno < 0)
    {
        nume *= -1;
        deno *= -1;
    }
    else if (nume > 0 && deno < 0)
    {
        nume *= -1;
        deno *= -1;
    }

    while (deno_ % nume_ != 0)
    {
        int temp = deno_;
        deno_ = nume_;
        nume_ = temp % nume_;
    }
    nume /= nume_;
    deno /= nume_;
    
    /* 也可以这么写
    while (nume_ != deno_)
    {
        if (nume_ > deno_)
            nume_ -= deno_;
        else
            deno_ -= nume_;
    }
    nume /= nume_;
    deno /= nume_;*/
}
istream &operator>>(istream &in, CFraction &x)
{
    char temp;
    in >> x.nume >> temp >> x.deno;
    return in;
}
ostream &operator<<(ostream &out, CFraction x)
{
    if (x.deno != 1)
        out << x.nume << '/' << x.deno;
    else
        out << x.nume;
    return out;
}
CFraction operator+(const  CFraction &c1, const  CFraction &c2)
{
    CFraction temp(c1.nume * c2.deno + c2.nume * c1.deno, c1.deno * c2.deno);
    temp.simplify();
    return temp;
}
CFraction operator-(const  CFraction &c1, const  CFraction &c2)
{
    CFraction temp(c1.nume * c2.deno - c2.nume * c1.deno, c1.deno * c2.deno);
    temp.simplify();
    return temp;
}
CFraction operator*(const  CFraction &c1, const  CFraction &c2)
{
    CFraction temp(c1.nume * c2.nume, c1.deno * c2.deno);
    temp.simplify();
    return temp;
}
CFraction operator/(const  CFraction &c1, const  CFraction &c2)
{
    CFraction temp(c1.nume * c2.deno, c1.deno * c2.nume);
    temp.simplify();
    return temp;
}

int  main()
{
    CFraction  x, y, s;
    cout << "Input  x:  ";
    cin >> x;
    cout << "Input  y:  ";
    cin >> y;
    s = x + y;
    cout << "x+y=" << s << endl;
    s = x - y;
    cout << "x-y=" << s << endl;
    s = x * y;
    cout << "x*y=" << s << endl;
    s = x / y;
    cout << "x/y=" << s << endl;
    return  0;
}